#### Answer

$(1,5)$

#### Work Step by Step

For the first equation $x+y=6$, the $x$ and $y$ intercepts are found as $(6,0)$ and $(0,6)$ by substituting $0$ for $y$ and $x$ values in the equation respectively.
Similarly, for the second equation $x-y=-4$, the $x$ and $y$ intercepts are found as $(-4,0)$ and $(0,4)$ by substituting $0$ for $y$ and $x$ values in the equation respectively.
Now, graph each equation as a line passing through the intercepts. The lines intersect at point $(1,5)$ which represents the solution.
The graph is as below.